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Abraham B Selover 1853 - 1926

Abraham B Selover was born on October 13, 1853 in Queens County, New York United States. He was in a relationship with Alice Powell, and had a child Nettie Shannon. Abraham Selover died at age 73 years old on December 1, 1926. Family, friend, or fan, this family history biography is for you to remember Abraham B Selover.

Abraham B Selover

October 13, 1853

Queens County, New York, United States

December 1, 1926

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Abraham B Selover Abraham Selover (1853 - 1926)

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Abraham B Selover's History: 1853 - 1926

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10/13

1853

Birthday

October 13, 1853

Birthdate

Queens County, New York United States

Birthplace

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12/1

1926

Death

December 1, 1926

Death date

Unknown
Cause of death

Unknown
Death location

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Abraham B Selover lived 1 years shorter than the average family member when died at the age of 73.

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Abraham B Selover lived 1 years shorter than the average family member when died at the age of 73.

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Did you know?

In 1853, in the year that Abraham B Selover was born, in October, the Crimean War began. Allies the Ottoman Empire, France, Britain and Sardinia fought the Russian Empire in a war that began as a religious conflict but ended up being an effort to curb the expansion of the Russian Empire. The war ended in 1856.

Did you know?

In 1861, at the age of merely 8 years old, Abraham was alive when on August 5th, in order to help pay for the Civil War, the Federal government instituted the first income tax in the United States. The Revenue Act of 1861 was rescinded in 1862 but from 1861 through 1862, a flat tax was charged - 3% - on all income over $800, which included only 3% of households. In 1862, a broader tax was enacted.

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Abraham Selover's Family Tree & Friends

Abraham Selover's Family Tree

Parent

Abraham B Selover Oct 13, 1853 - Dec 1, 1926

Partner

Child

Sibling

Partnership

Alice Powell